What is expand (4x-5)e^{x^2-2x+1} ?

The solution to expand (4x-5)e^{x^2-2x+1} is 4e^{x^2-2x+1}x-5e^{x^2-2x+1}

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expand (4x-5)e^{x^2-2x+1}

expand

(4 x - 5) e^{x^{2} - 2 x + 1}

4 e^{x^{2} - 2 x + 1} x - 5 e^{x^{2} - 2 x + 1}

Solution steps

(4 x - 5) e^{x^{2} - 2 x + 1}

= e^{x^{2} - 2 x + 1} (4 x - 5)

Apply the distributive law:

a (b - c) = ab - a c

a = e^{x^{2} - 2 x + 1}, b = 4 x, c = 5

= e^{x^{2} - 2 x + 1} \cdot 4 x - e^{x^{2} - 2 x + 1} \cdot 5

= 4 e^{x^{2} - 2 x + 1} x - 5 e^{x^{2} - 2 x + 1}

(2 x + \frac{y}{4})^{16}

(100 - e^{2}) \cdot 200

- \frac{2 x + h}{x ^{2} ( x + h ) ^{2}}

x d y + (x - y) d x

(D^{2} + 2 D - 3) (4 e^{2 x})

What is expand (4x-5)e^{x^2-2x+1} ?
The solution to expand (4x-5)e^{x^2-2x+1} is 4e^{x^2-2x+1}x-5e^{x^2-2x+1}