What is expand e^tcos(t)U(t-1) ?

The solution to expand e^tcos(t)U(t-1) is e^ttUcos(t)-e^tUcos(t)

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expand e^tcos(t)U(t-1)

expand

e^{t} cos (t) U (t - 1)

e^{t} t U cos (t) - e^{t} U cos (t)

Solution steps

e^{t} cos (t) U (t - 1)

= e^{t} U cos (t) (t - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = e^{t} cos (t) U, b = t, c = 1

= e^{t} cos (t) U t - e^{t} cos (t) U \cdot 1

= e^{t} t U cos (t) - 1 \cdot e^{t} U cos (t)

Multiply:

1 \cdot e^{t} = e^{t}

= e^{t} t U cos (t) - e^{t} U cos (t)

2 (ln (x) + 1)

\frac{x + 1 - a}{( x + 1 ) ( x - 1 )}

(- e^{- x}) (2 - sin (2 x))

2 x (y + 1) d x

(200 - e^{2}) \cdot 100

What is expand e^tcos(t)U(t-1) ?
The solution to expand e^tcos(t)U(t-1) is e^ttUcos(t)-e^tUcos(t)