What is expand 1/((s+2)(s^2+2s+3)) ?

The solution to expand 1/((s+2)(s^2+2s+3)) is 1/(s^3+4s^2+7s+6)

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expand 1/((s+2)(s^2+2s+3))

expand

\frac{1}{( s + 2 ) ( s ^{2} + 2 s + 3 )}

\frac{1}{s ^{3} + 4 s ^{2} + 7 s + 6}

Solution steps

\frac{1}{( s + 2 ) ( s ^{2} + 2 s + 3 )}

Expand

(s + 2) (s^{2} + 2 s + 3) : s^{3} + 4 s^{2} + 7 s + 6

= \frac{1}{s ^{3} + 4 s ^{2} + 7 s + 6}

(1 + ln (x)) d x + (1 + ln (y)) d y

\frac{x + 8}{( x - 5 ) ( x + 5 )}

cos (2) (π - x)

\frac{2}{( x ^{6} + x ^{2} + 1 ) ^{2}}

(1 + x^{4} + x^{6})^{7}

What is expand 1/((s+2)(s^2+2s+3)) ?
The solution to expand 1/((s+2)(s^2+2s+3)) is 1/(s^3+4s^2+7s+6)