What is expand ((x^4-1)^2)/(x^4) ?

The solution to expand ((x^4-1)^2)/(x^4) is x^4-2+1/(x^4)

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expand ((x^4-1)^2)/(x^4)

expand

\frac{( x ^{4} - 1 ) ^{2}}{x ^{4}}

x^{4} - 2 + \frac{1}{x ^{4}}

Solution steps

\frac{( x ^{4} - 1 ) ^{2}}{x ^{4}}

(x^{4} - 1)^{2} = x^{8} - 2 x^{4} + 1

= \frac{x ^{8} - 2 x ^{4} + 1}{x ^{4}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{8} - 2 x ^{4} + 1}{x ^{4}} = \frac{x ^{8}}{x ^{4}} - \frac{2 x ^{4}}{x ^{4}} + \frac{1}{x ^{4}}

= \frac{x ^{8}}{x ^{4}} - \frac{2 x ^{4}}{x ^{4}} + \frac{1}{x ^{4}}

Cancel

\frac{x ^{8}}{x ^{4}} : x^{4}

= x^{4} - \frac{2 x ^{4}}{x ^{4}} + \frac{1}{x ^{4}}

Cancel

\frac{2 x ^{4}}{x ^{4}} : 2

= x^{4} - 2 + \frac{1}{x ^{4}}

\frac{x ^{4}}{( x ^{2} + 3 ) ^{2}}

α (2, 2, 0) β (0, - 2, - 1) γ (2, 2, - 2)

\frac{2 ( u - 5 )}{3}

\frac{x ^{5} - x + 1}{( x - 2 ) ( x + 1 )}

\frac{( x - 2 ) ^{3}}{x ^{2}}

What is expand ((x^4-1)^2)/(x^4) ?
The solution to expand ((x^4-1)^2)/(x^4) is x^4-2+1/(x^4)