What is expand ((x^3+2)^3)/3 ?

The solution to expand ((x^3+2)^3)/3 is (x^9)/3+2x^6+4x^3+8/3

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expand ((x^3+2)^3)/3

expand

\frac{( x ^{3} + 2 ) ^{3}}{3}

\frac{x ^{9}}{3} + 2 x^{6} + 4 x^{3} + \frac{8}{3}

Solution steps

\frac{( x ^{3} + 2 ) ^{3}}{3}

(x^{3} + 2)^{3} = x^{9} + 6 x^{6} + 12 x^{3} + 8

= \frac{x ^{9} + 6 x ^{6} + 12 x ^{3} + 8}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{9} + 6 x ^{6} + 12 x ^{3} + 8}{3} = \frac{x ^{9}}{3} + \frac{6 x ^{6}}{3} + \frac{12 x ^{3}}{3} + \frac{8}{3}

= \frac{x ^{9}}{3} + \frac{6 x ^{6}}{3} + \frac{12 x ^{3}}{3} + \frac{8}{3}

Divide the numbers:

\frac{6}{3} = 2

= \frac{x ^{9}}{3} + 2 x^{6} + \frac{12 x ^{3}}{3} + \frac{8}{3}

Divide the numbers:

\frac{12}{3} = 4

= \frac{x ^{9}}{3} + 2 x^{6} + 4 x^{3} + \frac{8}{3}

A (2, - \frac{π}{3})

\frac{e ^{(2 z)}}{( z - 1 ) ^{3}}

cos (2) (x + \frac{π}{2})

(2 x + 3) d x + (2 y - 2) d y

sin (x (a + b)) + sin (x (a - b))

What is expand ((x^3+2)^3)/3 ?
The solution to expand ((x^3+2)^3)/3 is (x^9)/3+2x^6+4x^3+8/3