What is expand (3x^2-8(y+2))/(2y) ?

The solution to expand (3x^2-8(y+2))/(2y) is (3x^2)/(2y)-4-8/y

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expand (3x^2-8(y+2))/(2y)

expand

\frac{3 x ^{2} - 8 ( y + 2 )}{2 y}

\frac{3 x ^{2}}{2 y} - 4 - \frac{8}{y}

Solution steps

\frac{3 x ^{2} - 8 ( y + 2 )}{2 y}

Expand

3 x^{2} - 8 (y + 2) : 3 x^{2} - 8 y - 16

= \frac{3 x ^{2} - 8 y - 16}{2 y}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 x ^{2} - 8 y - 16}{2 y} = \frac{3 x ^{2}}{2 y} - \frac{8 y}{2 y} - \frac{16}{2 y}

= \frac{3 x ^{2}}{2 y} - \frac{8 y}{2 y} - \frac{16}{2 y}

Cancel

\frac{8 y}{2 y} : 4

= \frac{3 x ^{2}}{2 y} - 4 - \frac{16}{2 y}

Divide the numbers:

\frac{16}{2} = 8

= \frac{3 x ^{2}}{2 y} - 4 - \frac{8}{y}

(1 + y^{2}) d x + (x y) d y

(a - b)^{2} + (c - d)^{2}

2 π^{r} (r + h)

3 (y + 2) d x

cos (2) (π + x)

What is expand (3x^2-8(y+2))/(2y) ?
The solution to expand (3x^2-8(y+2))/(2y) is (3x^2)/(2y)-4-8/y