What is expand 1/(s(s+1)(s^2+4s+13)) ?

The solution to expand 1/(s(s+1)(s^2+4s+13)) is 1/(s^4+5s^3+17s^2+13s)

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expand 1/(s(s+1)(s^2+4s+13))

expand

\frac{1}{s ( s + 1 ) ( s ^{2} + 4 s + 13 )}

\frac{1}{s ^{4} + 5 s ^{3} + 17 s ^{2} + 13 s}

Solution steps

\frac{1}{s ( s + 1 ) ( s ^{2} + 4 s + 13 )}

Expand

s (s + 1) (s^{2} + 4 s + 13) : s^{4} + 5 s^{3} + 17 s^{2} + 13 s

= \frac{1}{s ^{4} + 5 s ^{3} + 17 s ^{2} + 13 s}

18

(a + \frac{b}{c}) (d - e)

(A - B) \circ B

4 a - 74 a + 7

\frac{( x ^{2} - 3 ) ^{2}}{x ^{5}}

What is expand 1/(s(s+1)(s^2+4s+13)) ?
The solution to expand 1/(s(s+1)(s^2+4s+13)) is 1/(s^4+5s^3+17s^2+13s)