What is expand 1/((1-ax)(1-bx)(1-cx)) ?

The solution to expand 1/((1-ax)(1-bx)(1-cx)) is 1/(1-cx-bx+bcx^2-ax+acx^2+abx^2-abcx^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 1/((1-ax)(1-bx)(1-cx))

expand

\frac{1}{( 1 - a x ) ( 1 - b x ) ( 1 - c x )}

\frac{1}{1 - c x - b x + b c x ^{2} - a x + a c x ^{2} + ab x ^{2} - ab c x ^{3}}

Solution steps

\frac{1}{( 1 - a x ) ( 1 - b x ) ( 1 - c x )}

Expand

(1 - a x) (1 - b x) (1 - c x) : 1 - c x - b x + b c x^{2} - a x + a c x^{2} + ab x^{2} - ab c x^{3}

= \frac{1}{1 - c x - b x + b c x ^{2} - a x + a c x ^{2} + ab x ^{2} - ab c x ^{3}}

(3 d + 8 e)^{3}

- 3 x (3 x + 2 x ln (x))

(\frac{x}{4 y ^{'} ( x )} + y)^{2}

p u n t os (2, - 1) y (\frac{1 , - 9}{7})

\frac{1}{90} (e^{8 x} + 8 e^{8 x} x)

What is expand 1/((1-ax)(1-bx)(1-cx)) ?
The solution to expand 1/((1-ax)(1-bx)(1-cx)) is 1/(1-cx-bx+bcx^2-ax+acx^2+abx^2-abcx^3)