What is expand ((3x+2)(-3x+2))/9 ?

The solution to expand ((3x+2)(-3x+2))/9 is -x^2+4/9

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expand ((3x+2)(-3x+2))/9

expand

\frac{( 3 x + 2 ) ( - 3 x + 2 )}{9}

- x^{2} + \frac{4}{9}

Solution steps

\frac{( 3 x + 2 ) ( - 3 x + 2 )}{9}

Expand

(3 x + 2) (- 3 x + 2) : 4 - 9 x^{2}

= \frac{4 - 9 x ^{2}}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 - 9 x ^{2}}{9} = \frac{4}{9} - \frac{9 x ^{2}}{9}

= \frac{4}{9} - \frac{9 x ^{2}}{9}

Divide the numbers:

\frac{9}{9} = 1

= \frac{4}{9} - x^{2}

Rewrite in standard form

= - x^{2} + \frac{4}{9}

a + b e^{a (t - t_{0})}

\frac{( x + 7 ) ( x + 5 )}{x + 4}

2 (x + \frac{π}{3})

\frac{1}{( x ^{3} - 1 ) ^{2}}

(2 + 2) (2 + 1)^{n}

What is expand ((3x+2)(-3x+2))/9 ?
The solution to expand ((3x+2)(-3x+2))/9 is -x^2+4/9