What is expand (x+1)*ln^2(x+1) ?

The solution to expand (x+1)*ln^2(x+1) is xln^2(x+1)+ln^2(x+1)

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expand (x+1)*ln^2(x+1)

expand

(x + 1) \cdot ln^{2} (x + 1)

x ln^{2} (x + 1) + ln^{2} (x + 1)

Solution steps

(x + 1) ln^{2} (x + 1)

= ln^{2} (x + 1) (x + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = ln^{2} (x + 1), b = x, c = 1

= ln^{2} (x + 1) x + ln^{2} (x + 1) \cdot 1

= x ln^{2} (x + 1) + 1 \cdot ln^{2} (x + 1)

Multiply:

1 \cdot ln^{2} (x + 1) = ln^{2} (x + 1)

= x ln^{2} (x + 1) + ln^{2} (x + 1)

K (1 + \frac{1}{I s} + d s)

e^{3 t} h (t - 1)

\frac{x ^{2} + 4}{x ^{2} ( x - 4 )}

C (- 2, - 5)

\frac{x + 6}{( x - 6 ) ^{2}}

What is expand (x+1)*ln^2(x+1) ?
The solution to expand (x+1)*ln^2(x+1) is xln^2(x+1)+ln^2(x+1)