What is expand (s-1)/(s(s-3)(s+3)) ?

The solution to expand (s-1)/(s(s-3)(s+3)) is (s-1)/(s^3-9s)

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expand (s-1)/(s(s-3)(s+3))

expand

\frac{s - 1}{s ( s - 3 ) ( s + 3 )}

\frac{s - 1}{s ^{3} - 9 s}

Solution steps

\frac{s - 1}{s ( s - 3 ) ( s + 3 )}

Expand

s (s - 3) (s + 3) : s^{3} - 9 s

= \frac{s - 1}{s ^{3} - 9 s}

(t - 1) H (t - 1)

\frac{18 - 12 x}{( 4 x - 1 ) ( x - 4 )}

\frac{- 2 x - 18}{( 3 x + 1 ) ( x - 4 )}

- \frac{( x - 1 ) ( x ^{2} + 2 x - 90 )}{30}

\frac{( x - 6 ) ( x - 3 )}{4}

What is expand (s-1)/(s(s-3)(s+3)) ?
The solution to expand (s-1)/(s(s-3)(s+3)) is (s-1)/(s^3-9s)