What is expand ((x-3)(x-2))/((x+4)(2x-1)) ?

The solution to expand ((x-3)(x-2))/((x+4)(2x-1)) is (x^2-5x+6)/(2x^2+7x-4)

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expand ((x-3)(x-2))/((x+4)(2x-1))

expand

\frac{( x - 3 ) ( x - 2 )}{( x + 4 ) ( 2 x - 1 )}

\frac{x ^{2} - 5 x + 6}{2 x ^{2} + 7 x - 4}

Solution steps

\frac{( x - 3 ) ( x - 2 )}{( x + 4 ) ( 2 x - 1 )}

Expand

(x + 4) (2 x - 1) : 2 x^{2} + 7 x - 4

= \frac{( x - 3 ) ( x - 2 )}{2 x ^{2} + 7 x - 4}

Expand

(x - 3) (x - 2) : x^{2} - 5 x + 6

= \frac{x ^{2} - 5 x + 6}{2 x ^{2} + 7 x - 4}

\frac{( 5 - t ) ^{2}}{( t + 6 )}

\frac{3 ( 1 + 3 )}{2}

(e^{- 1600 t} - e^{- 400 t})^{2}

(f \circ g + hk) (x)

(x^{2} + 6 x) cos (x) d x

What is expand ((x-3)(x-2))/((x+4)(2x-1)) ?
The solution to expand ((x-3)(x-2))/((x+4)(2x-1)) is (x^2-5x+6)/(2x^2+7x-4)