What is expand (3ydx+6dx-xdy=0) 1/(ydx) ?

The solution to expand (3ydx+6dx-xdy=0) 1/(ydx) is 3+6/y-(xdy)/(ydx)=0

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expand (3ydx+6dx-xdy=0) 1/(ydx)

expand

(3 y d x + 6 d x - x d y = 0) \frac{1}{y d x}

3 + \frac{6}{y} - \frac{x d y}{y d x} = 0

Solution steps

(3 y d x + 6 d x - x d y = 0) \frac{1}{y d x}

= \frac{1}{y d x} (3 y d x + 6 d x - 0 = x d y)

Distribute parentheses

= \frac{1}{y d x} \cdot 3 y d x + \frac{1}{y d x} \cdot 6 d x + \frac{1}{y d x} (- x d y = 0)

Apply minus-plus rules

+ (- a) = - a

3 \cdot \frac{1}{y d x} y d x + 6 \cdot \frac{1}{y d x} d x - \frac{1}{y d x} x d y = 0

Expand

3 \cdot \frac{1}{y d x} y d x + 6 \cdot \frac{1}{y d x} d x - \frac{1}{y d x} x d y : 3 + \frac{6}{y} - \frac{x d y}{y d x}

3 + \frac{6}{y} - \frac{x d y}{y d x} = 0

\frac{4}{( 4 - x ) ^{2}}

C (- 2, - 5) P (- 4, 5)

\frac{3 x + 15}{( x + 6 ) ( x + 3 )}

\frac{5}{( 3 + x ^{2} ) ^{10}}

(x^{3} + y^{3}) d y

What is expand (3ydx+6dx-xdy=0) 1/(ydx) ?
The solution to expand (3ydx+6dx-xdy=0) 1/(ydx) is 3+6/y-(xdy)/(ydx)=0