What is expand (x^2-1)p'(x)n ?

The solution to expand (x^2-1)p'(x)n is nx^2p'(x)-np'(x)

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expand (x^2-1)p'(x)n

expand

(x^{2} - 1) p^{'} (x) n

n x^{2} p' (x) - n p' (x)

Solution steps

(x^{2} - 1) p^{'} (x) n

= n (x^{2} - 1) p^{^{'}} (x)

Apply the distributive law:

a (b - c) = ab - a c

a = p^{'} (x) n, b = x^{2}, c = 1

= p^{^{'}} (x) n x^{2} - p^{^{'}} (x) n \cdot 1

= n x^{2} p^{^{'}} (x) - 1 \cdot n p^{^{'}} (x)

Multiply:

1 \cdot n = n

= n x^{2} p^{^{'}} (x) - n p^{^{'}} (x)

\frac{2}{( x + 1 ) ( - x + 1 )}

A (3, 4) B (3, - 5)

\frac{3 ( b + a )}{4}

\frac{x ^{2} + 4 x + 3}{( x + 2 ) ^{2}}

\frac{x ^{2}}{y ( 1 + x ^{3} )}

What is expand (x^2-1)p'(x)n ?
The solution to expand (x^2-1)p'(x)n is nx^2p'(x)-np'(x)