What is expand (9x+3)e^{2x^2+3} ?

The solution to expand (9x+3)e^{2x^2+3} is 9e^{2x^2+3}x+3e^{2x^2+3}

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expand (9x+3)e^{2x^2+3}

expand

(9 x + 3) e^{2 x^{2} + 3}

9 e^{2 x^{2} + 3} x + 3 e^{2 x^{2} + 3}

Solution steps

(9 x + 3) e^{2 x^{2} + 3}

= e^{2 x^{2} + 3} (9 x + 3)

Apply the distributive law:

a (b + c) = ab + a c

a = e^{2 x^{2} + 3}, b = 9 x, c = 3

= e^{2 x^{2} + 3} \cdot 9 x + e^{2 x^{2} + 3} \cdot 3

= 9 e^{2 x^{2} + 3} x + 3 e^{2 x^{2} + 3}

\frac{2 x}{( 2 x - 1 ) ( x + 3 )}

(cos (y)) (x + d x)

\frac{1}{( s + 3 ) ( s + 7 )}

\frac{x + 1}{( x - 2 ) ^{2}}

y d x + (2 x + 3 y) d y

What is expand (9x+3)e^{2x^2+3} ?
The solution to expand (9x+3)e^{2x^2+3} is 9e^{2x^2+3}x+3e^{2x^2+3}