What is expand 1/((j)(j+1)(j+0.5)) ?

The solution to expand 1/((j)(j+1)(j+0.5)) is 1/(j^3+1.5j^2+0.5j)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 1/((j)(j+1)(j+0.5))

expand

\frac{1}{( j ) ( j + 1 ) ( j + 0.5 )}

\frac{1}{j ^{3} + 1.5 j ^{2} + 0.5 j}

Solution steps

\frac{1}{( j ) ( j + 1 ) ( j + 0.5 )}

Remove parentheses:

(a) = a

= \frac{1}{j ( j + 1 ) ( j + 0.5 )}

Expand

j (j + 1) (j + 0.5) : j^{3} + 1.5 j^{2} + 0.5 j

= \frac{1}{j ^{3} + 1.5 j ^{2} + 0.5 j}

\frac{x + 1}{( x - 1 ) ^{2} ( x ^{2} + 1 )}

\frac{( 1 - cosh ( x ) ) ^{2}}{h}

\frac{( x ^{2} + 3 x )}{( 3 x + 1 ) ^{2}}

(1, 1) y (- 1, - 1)

\frac{3}{( x ^{2} + 4 ) ^{3}}

What is expand 1/((j)(j+1)(j+0.5)) ?
The solution to expand 1/((j)(j+1)(j+0.5)) is 1/(j^3+1.5j^2+0.5j)