What is expand ((x-3)(x-4))/6 ?

The solution to expand ((x-3)(x-4))/6 is (x^2)/6-(7x)/6+2

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expand ((x-3)(x-4))/6

expand

\frac{( x - 3 ) ( x - 4 )}{6}

\frac{x ^{2}}{6} - \frac{7 x}{6} + 2

Solution steps

\frac{( x - 3 ) ( x - 4 )}{6}

Expand

(x - 3) (x - 4) : x^{2} - 7 x + 12

= \frac{x ^{2} - 7 x + 12}{6}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} - 7 x + 12}{6} = \frac{x ^{2}}{6} - \frac{7 x}{6} + \frac{12}{6}

= \frac{x ^{2}}{6} - \frac{7 x}{6} + \frac{12}{6}

Divide the numbers:

\frac{12}{6} = 2

= \frac{x ^{2}}{6} - \frac{7 x}{6} + 2

e^{x} (2 x + 2 x)

\frac{x + 4}{( x - 7 ) ( x + 3 )}

\frac{( x + 5 ) ^{2}}{x ^{2} + 25}

\frac{a ^{2} + 2 ab + b}{( a + b ) ^{2}}

\frac{x ( 1 + e ^{- x} )}{1 - e ^{- x}}

What is expand ((x-3)(x-4))/6 ?
The solution to expand ((x-3)(x-4))/6 is (x^2)/6-(7x)/6+2