What is expand-(x^2-1)(x+Δx+5) ?

The solution to expand-(x^2-1)(x+Δx+5) is -x^3-Δx^3-5x^2+x+Δx+5

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expand-(x^2-1)(x+Δx+5)

expand

- (x^{2} - 1) (x + Δ x + 5)

- x^{3} - Δ x^{3} - 5 x^{2} + x + Δ x + 5

Solution steps

- (x^{2} - 1) (x + Δ x + 5)

Expand

(x^{2} - 1) (x + Δ x + 5) : x^{3} + Δ x^{3} + 5 x^{2} - x - Δ x - 5

= - (x^{3} + Δ x^{3} + 5 x^{2} - x - Δ x - 5)

Distribute parentheses

= - (x^{3}) - (Δ x^{3}) - (5 x^{2}) - (- x) - (- Δ x) - (- 5)

Apply minus-plus rules

- (- a) = a, - (a) = - a

= - x^{3} - Δ x^{3} - 5 x^{2} + x + Δ x + 5

\frac{k x + g}{( x - h ) ^{2}}

- \frac{( x + y ) ^{2} y - y}{x}

\frac{5 s + 13}{s ( s ^{2} + 4 s + 13 )}

\frac{( x y - x ) x}{y ( y x - y )}

(9 ab c^{3}) (14 b c^{2})

What is expand-(x^2-1)(x+Δx+5) ?
The solution to expand-(x^2-1)(x+Δx+5) is -x^3-Δx^3-5x^2+x+Δx+5