What is expand 1/((1-x)(B-x)(D-x)) ?

The solution to expand 1/((1-x)(B-x)(D-x)) is 1/(BD-Bx-Dx+x^2-BDx+Bx^2+Dx^2-x^3)

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expand 1/((1-x)(B-x)(D-x))

expand

\frac{1}{( 1 - x ) ( B - x ) ( D - x )}

\frac{1}{B D - B x - D x + x ^{2} - B D x + B x ^{2} + D x ^{2} - x ^{3}}

Solution steps

\frac{1}{( 1 - x ) ( B - x ) ( D - x )}

Expand

(1 - x) (B - x) (D - x) : B D - B x - D x + x^{2} - B D x + B x^{2} + D x^{2} - x^{3}

= \frac{1}{B D - B x - D x + x ^{2} - B D x + B x ^{2} + D x ^{2} - x ^{3}}

(e^{x} - 1) + (e^{x} - x)^{2}

4 (y + 4 = 32)

\frac{( 1 + e ^{2 x} ) ^{4}}{2 x}

(3 x^{3} y + y) d x + (y^{2} - x^{3}) d y

\frac{( 1 + x )}{( x - 1 ) ^{2}}

What is expand 1/((1-x)(B-x)(D-x)) ?
The solution to expand 1/((1-x)(B-x)(D-x)) is 1/(BD-Bx-Dx+x^2-BDx+Bx^2+Dx^2-x^3)