What is expand (2x^2+3x-4)-(x^2+x=8) ?

The solution to expand (2x^2+3x-4)-(x^2+x=8) is x^2+2x-4=8

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expand (2x^2+3x-4)-(x^2+x=8)

expand

(2 x^{2} + 3 x - 4) - (x^{2} + x = 8)

x^{2} + 2 x - 4 = 8

Solution steps

(2 x^{2} + 3 x - 4) - (x^{2} + x = 8)

= (2 x^{2} + 3 x - 4) - (x^{2} + 8 = x)

- (x^{2} + x = 8) : - x^{2} - x = 8

(2 x^{2} + 3 x - 4) - x^{2} - x = 8

Expand

(2 x^{2} + 3 x - 4) - x^{2} - x : x^{2} + 2 x - 4

x^{2} + 2 x - 4 = 8

(1 - 2 x) e^{2 x}

(2 + \frac{8}{5} x)^{8}

\frac{x ^{3}}{x}

(n + 1)! \cdot (n + 2)

\frac{( 4 x ^{2} - 16 x + 7 ) ^{5}}{40}

What is expand (2x^2+3x-4)-(x^2+x=8) ?
The solution to expand (2x^2+3x-4)-(x^2+x=8) is x^2+2x-4=8