What is expand (x^2-4x-1)/((x+4)(x+2)) ?

The solution to expand (x^2-4x-1)/((x+4)(x+2)) is (x^2-4x-1)/(x^2+6x+8)

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expand (x^2-4x-1)/((x+4)(x+2))

expand

\frac{x ^{2} - 4 x - 1}{( x + 4 ) ( x + 2 )}

\frac{x ^{2} - 4 x - 1}{x ^{2} + 6 x + 8}

Solution steps

\frac{x ^{2} - 4 x - 1}{( x + 4 ) ( x + 2 )}

Expand

(x + 4) (x + 2) : x^{2} + 6 x + 8

= \frac{x ^{2} - 4 x - 1}{x ^{2} + 6 x + 8}

(2 - i) (4_{180}^{\circ})

X (X^{^{'}} + Y)

(9 df - 7)^{3}

\frac{( 2 - w ) ^{3}}{w ^{2}}

\frac{( n ^{2} - 36 ) ^{2}}{36 n ^{2}}

What is expand (x^2-4x-1)/((x+4)(x+2)) ?
The solution to expand (x^2-4x-1)/((x+4)(x+2)) is (x^2-4x-1)/(x^2+6x+8)