What is expand ((3x+2)(2x+1))/(x+3) ?

The solution to expand ((3x+2)(2x+1))/(x+3) is (6x^2+7x+2)/(x+3)

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expand ((3x+2)(2x+1))/(x+3)

expand

\frac{( 3 x + 2 ) ( 2 x + 1 )}{x + 3}

\frac{6 x ^{2} + 7 x + 2}{x + 3}

Solution steps

\frac{( 3 x + 2 ) ( 2 x + 1 )}{x + 3}

Expand

(3 x + 2) (2 x + 1) : 6 x^{2} + 7 x + 2

= \frac{6 x ^{2} + 7 x + 2}{x + 3}

\frac{( 5 - b x ^{2} ) ^{5}}{10 b}

\frac{9 x ^{2}}{( x ^{3} + 4 ) ^{4}}

lo g_{10} (4) x^{2} y

\frac{1}{1 + ( x - 1 )}

2 δ (x - 2)

What is expand ((3x+2)(2x+1))/(x+3) ?
The solution to expand ((3x+2)(2x+1))/(x+3) is (6x^2+7x+2)/(x+3)