What is expand (8x(4x+9))/((9x-4)^2) ?

The solution to expand (8x(4x+9))/((9x-4)^2) is (32x^2+72x)/(81x^2-72x+16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (8x(4x+9))/((9x-4)^2)

expand

\frac{8 x ( 4 x + 9 )}{( 9 x - 4 ) ^{2}}

\frac{32 x ^{2} + 72 x}{81 x ^{2} - 72 x + 16}

Solution steps

\frac{8 x ( 4 x + 9 )}{( 9 x - 4 ) ^{2}}

(9 x - 4)^{2} = 81 x^{2} - 72 x + 16

= \frac{8 x ( 4 x + 9 )}{81 x ^{2} - 72 x + 16}

Expand

8 x (4 x + 9) : 32 x^{2} + 72 x

= \frac{32 x ^{2} + 72 x}{81 x ^{2} - 72 x + 16}

\frac{( m - 3 ) ( m + 6 )}{m + 3}

2 (5 v + 3) - 4 (7 v + 1 = - 88)

(e^{- t} + e^{- 2 t}) u (t)

\frac{( x + 1 ) ( 2 x + 1 ) ( 2 x + 3 )}{3}

\frac{( y + 3 ) ( x - 1 )}{( y - 2 ) ( x + 4 )}

What is expand (8x(4x+9))/((9x-4)^2) ?
The solution to expand (8x(4x+9))/((9x-4)^2) is (32x^2+72x)/(81x^2-72x+16)