What is expand (2x+y=5,)(-x+y=2) ?

The solution to expand (2x+y=5,)(-x+y=2) is -2x^2+2xy=2

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expand (2x+y=5,)(-x+y=2)

expand

(2 x + y = 5,) (- x + y = 2)

- 2 x^{2} + 2 x y = 2

Solution steps

(2 x + y = 5,) (- x + y = 2)

= (2 x + 5 =, y) (- x + 2 = y)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 2 x, b = y = 5,, c = - x, d = y = 2

2 x (- x) + 2 x y = 2 + y = 5, (- x) + y = 5, y = 2

Apply minus-plus rules

+ (- a) = - a

- 2 xx + 2 x y = 2 - y = 5, x + y = 5, y = 2

Expand

- 2 xx + 2 x y : - 2 x^{2} + 2 x y

- 2 x^{2} + 2 x y = 2

\frac{4 s - 2}{( 4 s ^{2} - 4 s + 5 ) ^{2}}

l imh \Rightarrow 0 (8 + h) 2 - 64 h

\frac{4 x + 1}{( x + 1 ) ^{2} ( x - 2 )}

- \frac{x + 3}{4 ( y - 1 )}

\frac{20 e ^{4}}{( 1 + e ^{4} ) ^{2}}

What is expand (2x+y=5,)(-x+y=2) ?
The solution to expand (2x+y=5,)(-x+y=2) is -2x^2+2xy=2