What is expand (2x-1)^2ln(3x+4) ?

The solution to expand (2x-1)^2ln(3x+4) is 4x^2ln(3x+4)-4xln(3x+4)+ln(3x+4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2x-1)^2ln(3x+4)

expand

(2 x - 1)^{2} ln (3 x + 4)

4 x^{2} ln (3 x + 4) - 4 x ln (3 x + 4) + ln (3 x + 4)

Solution steps

(2 x - 1)^{2} ln (3 x + 4)

(2 x - 1)^{2} = 4 x^{2} - 4 x + 1

= ln (3 x + 4) (4 x^{2} - 4 x + 1)

= ln (3 x + 4) (4 x^{2} - 4 x + 1)

Distribute parentheses

= ln (3 x + 4) \cdot 4 x^{2} + ln (3 x + 4) (- 4 x) + ln (3 x + 4) \cdot 1

Apply minus-plus rules

+ (- a) = - a

= 4 x^{2} ln (3 x + 4) - 4 x ln (3 x + 4) + 1 \cdot ln (3 x + 4)

Multiply:

1 \cdot ln (3 x + 4) = ln (3 x + 4)

= 4 x^{2} ln (3 x + 4) - 4 x ln (3 x + 4) + ln (3 x + 4)

sin (t (t - \frac{π}{6}))

(x - 2) e^{3}

\frac{( 2 x + 1 ) n ^{2}}{( n + 1 ) ^{2}}

(x^{2} + 6 x + 6) e^{x}

(x - 2) e^{2}

What is expand (2x-1)^2ln(3x+4) ?
The solution to expand (2x-1)^2ln(3x+4) is 4x^2ln(3x+4)-4xln(3x+4)+ln(3x+4)