What is expand ((x+3)(x^2-9x+26))/(48) ?

The solution to expand ((x+3)(x^2-9x+26))/(48) is (x^3}{48}-\frac{x^2)/8-x/(48)+13/8

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expand ((x+3)(x^2-9x+26))/(48)

expand

\frac{( x + 3 ) ( x ^{2} - 9 x + 26 )}{48}

\frac{x ^{3}}{48} - \frac{x ^{2}}{8} - \frac{x}{48} + \frac{13}{8}

Solution steps

\frac{( x + 3 ) ( x ^{2} - 9 x + 26 )}{48}

Expand

(x + 3) (x^{2} - 9 x + 26) : x^{3} - 6 x^{2} - x + 78

= \frac{x ^{3} - 6 x ^{2} - x + 78}{48}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} - 6 x ^{2} - x + 78}{48} = \frac{x ^{3}}{48} - \frac{6 x ^{2}}{48} - \frac{x}{48} + \frac{78}{48}

= \frac{x ^{3}}{48} - \frac{6 x ^{2}}{48} - \frac{x}{48} + \frac{78}{48}

Cancel

\frac{6 x ^{2}}{48} : \frac{x ^{2}}{8}

= \frac{x ^{3}}{48} - \frac{x ^{2}}{8} - \frac{x}{48} + \frac{78}{48}

Cancel

\frac{78}{48} : \frac{13}{8}

= \frac{x ^{3}}{48} - \frac{x ^{2}}{8} - \frac{x}{48} + \frac{13}{8}

\frac{( x ^{3} - 3 ) ^{9}}{x ^{18}}

\frac{5 ( 77 - 745 )}{2}

(x^{2} + π)^{4}

(a c - d b, a d + b c) (e, f)

\frac{x - 5}{( x + 1 ) ^{3}}

What is expand ((x+3)(x^2-9x+26))/(48) ?
The solution to expand ((x+3)(x^2-9x+26))/(48) is (x^3}{48}-\frac{x^2)/8-x/(48)+13/8