What is expand 1/((1-x)(b-x)(d-x)) ?

The solution to expand 1/((1-x)(b-x)(d-x)) is 1/(bd-bx-dx+x^2-bdx+bx^2+dx^2-x^3)

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expand 1/((1-x)(b-x)(d-x))

expand

\frac{1}{( 1 - x ) ( b - x ) ( d - x )}

\frac{1}{b d - b x - d x + x ^{2} - b d x + b x ^{2} + d x ^{2} - x ^{3}}

Solution steps

\frac{1}{( 1 - x ) ( b - x ) ( d - x )}

Expand

(1 - x) (b - x) (d - x) : b d - b x - d x + x^{2} - b d x + b x^{2} + d x^{2} - x^{3}

= \frac{1}{b d - b x - d x + x ^{2} - b d x + b x ^{2} + d x ^{2} - x ^{3}}

2 (x + Δ x) - 1

α (5, - 1, 2) + β (- 7, - 2, 11)

(5 y + 12 x yz - 10 + 6 x^{4}) - (12 +, + 4 x)

- \frac{2}{( 2 + h ) ^{2}}

\frac{2 x}{( 25 - x ^{2} ) ^{2}}

What is expand 1/((1-x)(b-x)(d-x)) ?
The solution to expand 1/((1-x)(b-x)(d-x)) is 1/(bd-bx-dx+x^2-bdx+bx^2+dx^2-x^3)