What is expand (4(4^{n+1}-16))/3 ?

The solution to expand (4(4^{n+1}-16))/3 is (4^{n+2})/3-64/3

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expand (4(4^{n+1}-16))/3

expand

\frac{4 ( 4 ^{n + 1} - 16 )}{3}

\frac{4 ^{n + 2}}{3} - \frac{64}{3}

Solution steps

\frac{4 ( 4 ^{n + 1} - 16 )}{3}

Expand

4 (4^{n + 1} - 16) : 4^{n + 2} - 64

= \frac{4 ^{n + 2} - 64}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 ^{n + 2} - 64}{3} = \frac{4 ^{n + 2}}{3} - \frac{64}{3}

= \frac{4 ^{n + 2}}{3} - \frac{64}{3}

- 4 x^{5} \cdot x^{4}

\frac{( y - x z ) ( z - x y ) ( x - yz )}{x yz}

\frac{a - b ( a - c )}{b + e}

\frac{x}{( x - 8 ) ( x ^{2} + 1 ) ^{3}}

(- 3, 4) y (4, - 6)

What is expand (4(4^{n+1}-16))/3 ?
The solution to expand (4(4^{n+1}-16))/3 is (4^{n+2})/3-64/3