What is expand (y-x=0,)(x+y=1) ?

The solution to expand (y-x=0,)(x+y=1) is yx+y^2=1

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expand (y-x=0,)(x+y=1)

expand

(y - x = 0,) (x + y = 1)

y x + y^{2} = 1

Solution steps

(y - x = 0,) (x + y = 1)

= (y - 0 =, x) (x + 1 = y)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = y, b = - x = 0,, c = x, d = y = 1

y x + yy = 1 + (- x = 0,) x + (- x = 0,) y = 1

Apply minus-plus rules

+ (- a) = - a

y x + yy = 1 - x = 0, x - x = 0, y = 1

Expand

y x + yy : y x + y^{2}

y x + y^{2} = 1

(3 e^{4} - 5 f)^{2}

\frac{( 1 - x ) ^{9}}{( 1 + x ) ^{7}}

e^{x} (- x^{2} + 2 x - 1)

(x + 2)^{5}

(t^{2} - 2 t) e^{1 - t^{3}}

What is expand (y-x=0,)(x+y=1) ?
The solution to expand (y-x=0,)(x+y=1) is yx+y^2=1