What is expand 1/(2e^{-x)(x+1)} ?

The solution to expand 1/(2e^{-x)(x+1)} is 1/(2e^{-x)x+2e^{-x}}

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expand 1/(2e^{-x)(x+1)}

expand

\frac{1}{2 e ^{- x} ( x + 1 )}

\frac{1}{2 e ^{- x} x + 2 e ^{- x}}

Solution steps

\frac{1}{2 e ^{- x} ( x + 1 )}

Expand

2 e^{- x} (x + 1) : 2 e^{- x} x + 2 e^{- x}

= \frac{1}{2 e ^{- x} x + 2 e ^{- x}}

- \frac{( tan ( θ ) - 3 ) ^{2}}{2}

\frac{( 3 x + 5 ) ( 3 x - 5 )}{3 ( 2 x - 5 )}

\frac{4 ( x + 5 ) ( x + 1 )}{( x + 3 ) ( x - 3 )}

6 (15)

(3 x + 4 y - 2 z = 5,) - (3 x - 9 y + 8 z = 9)

What is expand 1/(2e^{-x)(x+1)} ?
The solution to expand 1/(2e^{-x)(x+1)} is 1/(2e^{-x)x+2e^{-x}}