What is expand ((x+3)(2x+1))/4 ?

The solution to expand ((x+3)(2x+1))/4 is (x^2)/2+(7x)/4+3/4

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expand ((x+3)(2x+1))/4

expand

\frac{( x + 3 ) ( 2 x + 1 )}{4}

\frac{x ^{2}}{2} + \frac{7 x}{4} + \frac{3}{4}

Solution steps

\frac{( x + 3 ) ( 2 x + 1 )}{4}

Expand

(x + 3) (2 x + 1) : 2 x^{2} + 7 x + 3

= \frac{2 x ^{2} + 7 x + 3}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x ^{2} + 7 x + 3}{4} = \frac{2 x ^{2}}{4} + \frac{7 x}{4} + \frac{3}{4}

= \frac{2 x ^{2}}{4} + \frac{7 x}{4} + \frac{3}{4}

Cancel

\frac{2 x ^{2}}{4} : \frac{x ^{2}}{2}

= \frac{x ^{2}}{2} + \frac{7 x}{4} + \frac{3}{4}

\frac{x + 5}{( 2 x + 3 ) ( x + 4 )}

- y (ln (y) - tan (x) \cdot t) d x

\frac{1}{( n + 1 ) ( n - 1 )}

\frac{d ^{2}}{d x ^{2}} ((y) (4 x - 8))

\frac{1}{( a + 2 ) ^{2}}

What is expand ((x+3)(2x+1))/4 ?
The solution to expand ((x+3)(2x+1))/4 is (x^2)/2+(7x)/4+3/4