What is expand (3e^x+1)(ln(x)) ?

The solution to expand (3e^x+1)(ln(x)) is 3e^xln(x)+ln(x)

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expand (3e^x+1)(ln(x))

expand

(3 e^{x} + 1) (ln (x))

3 e^{x} ln (x) + ln (x)

Solution steps

(3 e^{x} + 1) (ln (x))

= (ln (x)) (3 e^{x} + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = (ln (x)), b = 3 e^{x}, c = 1

= (ln (x)) \cdot 3 e^{x} + (ln (x)) \cdot 1

= 3 e^{x} (ln (x)) + 1 \cdot (ln (x))

Simplify

3 e^{x} (ln (x)) + 1 \cdot (ln (x)) : 3 e^{x} ln (x) + ln (x)

= 3 e^{x} ln (x) + ln (x)

(3 x + 2 y = 18, 0) (2 x + 3 y = 50)

\frac{x}{( x + 4 ) \cdot ( 2 x - 1 )}

2 (3 x + 2 y = 8)

\frac{( e ^{x} + e ^{- x} ) ^{2}}{2}

(4^{x} + e^{x})^{2}

What is expand (3e^x+1)(ln(x)) ?
The solution to expand (3e^x+1)(ln(x)) is 3e^xln(x)+ln(x)