What is expand (x-6)/((x-4)(x+1)) ?

The solution to expand (x-6)/((x-4)(x+1)) is (x-6)/(x^2-3x-4)

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expand (x-6)/((x-4)(x+1))

expand

\frac{x - 6}{( x - 4 ) ( x + 1 )}

\frac{x - 6}{x ^{2} - 3 x - 4}

Solution steps

\frac{x - 6}{( x - 4 ) ( x + 1 )}

Expand

(x - 4) (x + 1) : x^{2} - 3 x - 4

= \frac{x - 6}{x ^{2} - 3 x - 4}

\frac{x ^{2} - 10 x + 2}{x ( x ^{2} - 1 )}

(800 - ln (2 q + 10)) (q)

x^{2} + x^{2}

\frac{( x + 1 ) ( x + 2 )}{( x - 1 ) ( x - 2 )}

31 x - 3 + 4

What is expand (x-6)/((x-4)(x+1)) ?
The solution to expand (x-6)/((x-4)(x+1)) is (x-6)/(x^2-3x-4)