What is expand pi^{e^{-1}}-arccos(-1) ?

The solution to expand pi^{e^{-1}}-arccos(-1) is pi^{1/e}-pi

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expand pi^{e^{-1}}-arccos(-1)

expand

π^{e^{- 1}} - arccos (- 1)

π^{\frac{1}{e}} - π

Decimal Notation

- 1.61792 \dots

Solution steps

π^{e^{- 1}} - arccos (- 1)

Use the following trivial identity:

arccos (- 1) = π

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= π^{e^{- 1}} - π

e^{- 1} = \frac{1}{e}

= π^{\frac{1}{e}} - π

(1 - 2) x

\frac{8 x + 71}{( x + 9 ) ( x + 8 )}

\frac{x ^{2} + x + 1}{( x + 1 ) ^{2}}

(2 x - y^{2}) d x + x y d y

C (2, - 4)

What is expand pi^{e^{-1}}-arccos(-1) ?
The solution to expand pi^{e^{-1}}-arccos(-1) is pi^{1/e}-pi