What is expand ((x+1)(x+2))/((2x+1)(x-3)) ?

The solution to expand ((x+1)(x+2))/((2x+1)(x-3)) is (x^2+3x+2)/(2x^2-5x-3)

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expand ((x+1)(x+2))/((2x+1)(x-3))

expand

\frac{( x + 1 ) ( x + 2 )}{( 2 x + 1 ) ( x - 3 )}

\frac{x ^{2} + 3 x + 2}{2 x ^{2} - 5 x - 3}

Solution steps

\frac{( x + 1 ) ( x + 2 )}{( 2 x + 1 ) ( x - 3 )}

Expand

(2 x + 1) (x - 3) : 2 x^{2} - 5 x - 3

= \frac{( x + 1 ) ( x + 2 )}{2 x ^{2} - 5 x - 3}

Expand

(x + 1) (x + 2) : x^{2} + 3 x + 2

= \frac{x ^{2} + 3 x + 2}{2 x ^{2} - 5 x - 3}

\frac{3 x + 2}{( x ) ( x + 4 ) ^{2}}

y (4 x + y) d x - 2 (x^{2} - y) d y

d (7 cos (x) + 2 e^{x})

\frac{2 x - 16}{( x + 2 ) ( x - 2 )}

A (5, - 9)

What is expand ((x+1)(x+2))/((2x+1)(x-3)) ?
The solution to expand ((x+1)(x+2))/((2x+1)(x-3)) is (x^2+3x+2)/(2x^2-5x-3)