What is log_{10}(40)+log_{10}(2.5) ?

The solution to log_{10}(40)+log_{10}(2.5) is 2

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simplify log_{10}(40)+log_{10}(2.5)

simplify

lo g_{10} (40) + lo g_{10} (2.5)

2

Solution steps

lo g_{10} (40) + lo g_{10} (2.5)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (40) + lo g_{10} (2.5) = lo g_{10} (40 \cdot 2.5)

= lo g_{10} (40 \cdot 2.5)

Multiply the numbers:

40 \cdot 2.5 = 100

= lo g_{10} (100)

Factor the number:

100 = 1 0^{2}

= lo g_{10} (1 0^{2})

Apply log rule:

lo g_{a} (a^{b}) = b

= 2

\frac{1}{20} \cdot \frac{8}{3}

- \frac{1}{2} - \frac{5}{2}

lo g_{3} (27) = x

9 (3 x + 9) = 14 - (x - 3)

2 x^{2} + 28 x + 98

What is log_{10}(40)+log_{10}(2.5) ?
The solution to log_{10}(40)+log_{10}(2.5) is 2