What is expand (x+Δx)(x+Δx-4) ?

The solution to expand (x+Δx)(x+Δx-4) is 2Δx^2+Δ^2x^2-4Δx+x^2-4x

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expand (x+Δx)(x+Δx-4)

expand

(x + Δ x) (x + Δ x - 4)

2Δ x^{2} + Δ^{2} x^{2} - 4Δ x + x^{2} - 4 x

Solution steps

(x + Δ x) (x + Δ x - 4)

Distribute parentheses

= xx + x Δ x + x (- 4) + Δ xx + Δ x Δ x + Δ x (- 4)

Apply minus-plus rules

+ (- a) = - a

= xx + Δ xx - 4 x + Δ xx + ΔΔ xx - 4Δ x

Simplify

xx + Δ xx - 4 x + Δ xx + ΔΔ xx - 4Δ x : 2Δ x^{2} + Δ^{2} x^{2} - 4Δ x + x^{2} - 4 x

= 2Δ x^{2} + Δ^{2} x^{2} - 4Δ x + x^{2} - 4 x

l im x \Rightarrow 2 (x^{2} - 4 x + 1)

\frac{1}{( 1 - 5 t ) ^{3}}

f (g (x + 1))

(1 + 3 i)^{6}

\frac{2 x ^{2} + 6 x + 5}{( x + 2 ) ( x + 1 )}

What is expand (x+Δx)(x+Δx-4) ?
The solution to expand (x+Δx)(x+Δx-4) is 2Δx^2+Δ^2x^2-4Δx+x^2-4x