What is expand 1/2 (-cos(x)+1=p(x)) ?

The solution to expand 1/2 (-cos(x)+1=p(x)) is -1/2 cos(x)+1/2 =p(x)

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expand 1/2 (-cos(x)+1=p(x))

expand

\frac{1}{2} (- cos (x) + 1 = p (x))

- \frac{1}{2} cos (x) + \frac{1}{2} = p (x)

Solution steps

\frac{1}{2} (- cos (x) + 1 = p (x))

Apply the distributive law:

a (b + c) = ab + a c

a = \frac{1}{2}, b = - cos (x), c = 1 = p (x)

\frac{1}{2} (- cos (x)) + \frac{1}{2} \cdot 1 = p (x)

Apply minus-plus rules

+ (- a) = - a

- \frac{1}{2} cos (x) + 1 \cdot \frac{1}{2} = p (x)

Expand

- \frac{1}{2} cos (x) + 1 \cdot \frac{1}{2} : - \frac{1}{2} cos (x) + \frac{1}{2}

- \frac{1}{2} cos (x) + \frac{1}{2} = p (x)

2 (n^{2} + 1) \frac{d m}{d n} + 6 nm

- \frac{4}{7 ( x ^{2} + 2 h x + h ^{2} )}

\frac{20 ( x ^{2} + 256 )}{x}

(x - 3) (\cdot + 2)

- \frac{3 ( 3 + 1 )}{2}

What is expand 1/2 (-cos(x)+1=p(x)) ?
The solution to expand 1/2 (-cos(x)+1=p(x)) is -1/2 cos(x)+1/2 =p(x)