What is expand 1/((x^2+2x+1)(x-1)) ?

The solution to expand 1/((x^2+2x+1)(x-1)) is 1/(x^3+x^2-x-1)

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expand 1/((x^2+2x+1)(x-1))

expand

\frac{1}{( x ^{2} + 2 x + 1 ) ( x - 1 )}

\frac{1}{x ^{3} + x ^{2} - x - 1}

Solution steps

\frac{1}{( x ^{2} + 2 x + 1 ) ( x - 1 )}

Expand

(x^{2} + 2 x + 1) (x - 1) : x^{3} + x^{2} - x - 1

= \frac{1}{x ^{3} + x ^{2} - x - 1}

- \frac{42 x ^{5} ( x + 1 )}{55 y ^{2}}

\frac{15}{x ( x - 5 )}

(e^{x} - 5)^{3}

\frac{9 x ( 2 x + 5 )}{( 5 x - 2 ) ^{2}}

\frac{( n - 1 ) ( n - 2 )}{2}

What is expand 1/((x^2+2x+1)(x-1)) ?
The solution to expand 1/((x^2+2x+1)(x-1)) is 1/(x^3+x^2-x-1)