What is expand ((1+2x^3)^2)/7 ?

The solution to expand ((1+2x^3)^2)/7 is (4x^6)/7+(4x^3)/7+1/7

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expand ((1+2x^3)^2)/7

expand

\frac{( 1 + 2 x ^{3} ) ^{2}}{7}

\frac{4 x ^{6}}{7} + \frac{4 x ^{3}}{7} + \frac{1}{7}

Solution steps

\frac{( 1 + 2 x ^{3} ) ^{2}}{7}

(1 + 2 x^{3})^{2} = 1 + 4 x^{3} + 4 x^{6}

= \frac{1 + 4 x ^{3} + 4 x ^{6}}{7}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{1 + 4 x ^{3} + 4 x ^{6}}{7} = \frac{1}{7} + \frac{4 x ^{3}}{7} + \frac{4 x ^{6}}{7}

= \frac{1}{7} + \frac{4 x ^{3}}{7} + \frac{4 x ^{6}}{7}

Rewrite in standard form

= \frac{4 x ^{6}}{7} + \frac{4 x ^{3}}{7} + \frac{1}{7}

\frac{( x - 2 ) ^{2}}{x ^{5}}

\frac{1}{x ( m - x )}

\frac{( x + 1 ) ^{2}}{( x ^{2} + 1 )}

\frac{3 s + 5}{( s + 1 ) ^{2} ( s + 2 )}

\frac{x + y}{( x + y ) ^{2} + 1}

What is expand ((1+2x^3)^2)/7 ?
The solution to expand ((1+2x^3)^2)/7 is (4x^6)/7+(4x^3)/7+1/7