What is expand x^2(3(y^4+1))dx ?

The solution to expand x^2(3(y^4+1))dx is 3x^2y^4dx+3x^2dx

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expand x^2(3(y^4+1))dx

expand

x^{2} (3 (y^{4} + 1)) d x

3 x^{2} y^{4} d x + 3 x^{2} d x

Solution steps

x^{2} (3 (y^{4} + 1)) d x

Remove parentheses:

(a) = a

= x^{2} \cdot 3 (y^{4} + 1) d x

= 3 x^{2} (y^{4} + 1) d x

Apply the distributive law:

a (b + c) = ab + a c

a = x^{2} \cdot 3 d x, b = y^{4}, c = 1

= x^{2} \cdot 3 d x y^{4} + x^{2} \cdot 3 d x \cdot 1

= 3 x^{2} y^{4} d x + 3 \cdot 1 \cdot x^{2} d x

Multiply the numbers:

3 \cdot 1 = 3

= 3 x^{2} y^{4} d x + 3 x^{2} d x

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What is expand x^2(3(y^4+1))dx ?
The solution to expand x^2(3(y^4+1))dx is 3x^2y^4dx+3x^2dx