What is expand 2e^t(2t,-5,t^2) ?

The solution to expand 2e^t(2t,-5,t^2) is 2*2e^tt,-2*5e^t,t^2

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expand 2e^t(2t,-5,t^2)

expand

2 e^{t} (2 t, - 5, t^{2})

2 \cdot 2 e^{t} t, - 2 \cdot 5 e^{t}, t^{2}

Solution steps

2 e^{t} (2 t, - 5, t^{2})

= 2 e^{t} (2, t - 5, t^{2})

Apply the distributive law:

a (b - c) = ab - a c

a = 2 e^{t}, b = 2 t,, c = 5, t^{2}

= 2 e^{t} \cdot 2 t, - 2 e^{t} \cdot 5, t^{2}

= 2 \cdot 2 e^{t} t, - 2 \cdot 5 e^{t}, t^{2}

\frac{6 ( n + 1 ) ( 2 n + 1 )}{n}

2 (x + 1) \frac{d}{d x} (x + 1)

\frac{a}{b ( c + n )}

4 (3 e^{6} - 1)

\frac{x ( 5 - 2 x )}{2}

What is expand 2e^t(2t,-5,t^2) ?
The solution to expand 2e^t(2t,-5,t^2) is 2*2e^tt,-2*5e^t,t^2