What are the solutions to the equation 0=x^2-8x+15 ?

The solutions to the equation 0=x^2-8x+15 are x=5,x=3

Find the zeros of 0=x^2-8x+15

The zeros of 0=x^2-8x+15 are x=5,x=3

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0 = x^{2} - 8 x + 15

x = 5, x = 3

Solution steps

0 = x^{2} - 8 x + 15

Switch sides

x^{2} - 8 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

x_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

x = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 5, x = 3

(- \frac{1}{6})^{5}

6 x^{2} + 126 x + 648

2 x + 3 \leq 9

(16 x^{5})^{\frac{5}{4}}

84 = 100 - 100 e - 0.04 x

What are the solutions to the equation 0=x^2-8x+15 ?
The solutions to the equation 0=x^2-8x+15 are x=5,x=3
Find the zeros of 0=x^2-8x+15
The zeros of 0=x^2-8x+15 are x=5,x=3