What is the d/(dt)((x)(5t^2+3t-7)) ?

The d/(dt)((x)(5t^2+3t-7)) is (dx)/(dt)(5t^2+3t-7)+(10t+3)x

What is the first d/(dt)((x)(5t^2+3t-7)) ?

The first d/(dt)((x)(5t^2+3t-7)) is (dx)/(dt)(5t^2+3t-7)+(10t+3)x

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\frac{d}{d t} ((x) (5 t^{2} + 3 t - 7))

\frac{d x}{d t} (5 t^{2} + 3 t - 7) + (10 t + 3) x

Solution steps

\frac{d}{d t} ((x) (5 t^{2} + 3 t - 7))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = 5 t^{2} + 3 t - 7

= \frac{d x}{d t} (5 t^{2} + 3 t - 7) + \frac{d}{d t} (5 t^{2} + 3 t - 7) x

\frac{d}{d t} (5 t^{2} + 3 t - 7) = 10 t + 3

= \frac{d x}{d t} (5 t^{2} + 3 t - 7) + (10 t + 3) x

\frac{( - a + b ) ^{2}}{a + b}

\frac{( 3 x ^{2} - 2 ) ^{5}}{5}

\frac{( 10 x - 5 ) 5}{2}

5 - (2 x = (43) - 1)

\frac{x ^{2} - 2 x - 3}{3 ( x - 1 )}

What is the d/(dt)((x)(5t^2+3t-7)) ?
The d/(dt)((x)(5t^2+3t-7)) is (dx)/(dt)(5t^2+3t-7)+(10t+3)x
What is the first d/(dt)((x)(5t^2+3t-7)) ?
The first d/(dt)((x)(5t^2+3t-7)) is (dx)/(dt)(5t^2+3t-7)+(10t+3)x