What is expand-(2(-y^2+9)^2)/(81) ?

The solution to expand-(2(-y^2+9)^2)/(81) is -(2y^4}{81}+\frac{4y^2)/9-2

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expand-(2(-y^2+9)^2)/(81)

expand

- \frac{2 ( - y ^{2} + 9 ) ^{2}}{81}

- \frac{2 y ^{4}}{81} + \frac{4 y ^{2}}{9} - 2

Solution steps

- \frac{2 ( - y ^{2} + 9 ) ^{2}}{81}

(- y^{2} + 9)^{2} = y^{4} - 18 y^{2} + 81

= - \frac{2 ( y ^{4} - 18 y ^{2} + 81 )}{81}

Expand

2 (y^{4} - 18 y^{2} + 81) : 2 y^{4} - 36 y^{2} + 162

= - \frac{2 y ^{4} - 36 y ^{2} + 162}{81}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 y ^{4} - 36 y ^{2} + 162}{81} = - (\frac{2 y ^{4}}{81}) - (- \frac{36 y ^{2}}{81}) - (\frac{162}{81})

= - (\frac{2 y ^{4}}{81}) - (- \frac{36 y ^{2}}{81}) - (\frac{162}{81})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{2 y ^{4}}{81} + \frac{36 y ^{2}}{81} - \frac{162}{81}

Cancel

\frac{36 y ^{2}}{81} : \frac{4 y ^{2}}{9}

= - \frac{2 y ^{4}}{81} + \frac{4 y ^{2}}{9} - \frac{162}{81}

Divide the numbers:

\frac{162}{81} = 2

= - \frac{2 y ^{4}}{81} + \frac{4 y ^{2}}{9} - 2

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What is expand-(2(-y^2+9)^2)/(81) ?
The solution to expand-(2(-y^2+9)^2)/(81) is -(2y^4}{81}+\frac{4y^2)/9-2