What is expand e^{1/(x-1)}*(2x+1) ?

The solution to expand e^{1/(x-1)}*(2x+1) is 2e^{1/(x-1)}x+e^{1/(x-1)}

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expand e^{1/(x-1)}*(2x+1)

expand

e^{\frac{1}{x - 1}} \cdot (2 x + 1)

2 e^{\frac{1}{x - 1}} x + e^{\frac{1}{x - 1}}

Solution steps

e^{\frac{1}{x - 1}} (2 x + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = e^{\frac{1}{x - 1}}, b = 2 x, c = 1

= e^{\frac{1}{x - 1}} \cdot 2 x + e^{\frac{1}{x - 1}} \cdot 1

= 2 e^{\frac{1}{x - 1}} x + 1 \cdot e^{\frac{1}{x - 1}}

Multiply:

1 \cdot e^{\frac{1}{x - 1}} = e^{\frac{1}{x - 1}}

= 2 e^{\frac{1}{x - 1}} x + e^{\frac{1}{x - 1}}

(2 x + vx) (v d x + x d v)

(1 + ln (x)) x^{2}

e^{t - 2} cos ((a + b + c) t)

(a + d t - c)^{2}

\frac{4 ( x + y ) ^{2}}{3}

What is expand e^{1/(x-1)}*(2x+1) ?
The solution to expand e^{1/(x-1)}*(2x+1) is 2e^{1/(x-1)}x+e^{1/(x-1)}