What is factor 2t^2+tu-6u^2 ?

The solution to factor 2t^2+tu-6u^2 is (2t-3u)(t+2u)

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factor 2t^2+tu-6u^2

factor

2 t^{2} + t u - 6 u^{2}

(2 t - 3 u) (t + 2 u)

Solution steps

2 t^{2} + t u - 6 u^{2}

Break the expression into groups

= (2 t^{2} - 3 t u) + (4 t u - 6 u^{2})

Factor out

t

from

2 t^{2} - 3 t u : t (2 t - 3 u)

Factor out

2 u

from

4 t u - 6 u^{2} : 2 u (2 t - 3 u)

= t (2 t - 3 u) + 2 u (2 t - 3 u)

Factor out common term

2 t - 3 u

= (2 t - 3 u) (t + 2 u)

(x + 5) (x + 1) > 0

lo g_{2} (7)

(a^{2} + 1) - b (a^{2} + 1)

\frac{k ^{2} - 11 k + 30}{9 k ^{2} - 90 k + 216}

x - 3 < 9

What is factor 2t^2+tu-6u^2 ?
The solution to factor 2t^2+tu-6u^2 is (2t-3u)(t+2u)