What is expand p(1,-3,2)yQ(2,1,-1) ?

The solution to expand p(1,-3,2)yQ(2,1,-1) is 1*pyQ,2,1,-1*pyQ,1-3pyQ,2*2,1,3,2*1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand p(1,-3,2)yQ(2,1,-1)

expand

p (1, - 3, 2) y Q (2, 1, - 1)

1 \cdot p y Q, 2, 1, - 1 \cdot p y Q, 1 - 3 p y Q, 2 \cdot 2, 1, 3, 2 \cdot 1

Solution steps

p (1, - 3, 2) y Q (2, 1, - 1)

= (1, - 3 \cdot 2,) (2 \cdot 1,, - 1) p y Q

Expand

(1, - 3, 2) (2, 1, - 1) : 1, 2, 1, - 1, 1 - 3, 2 \cdot 2, 1, 3, 2 \cdot 1

= p y Q (1, 2, 1, - 1, 1 - 3, 2 \cdot 2, 1, 3, 2 \cdot 1)

Expand

p y Q (1, 2, 1, - 1, 1 - 3, 2 \cdot 2, 1, 3, 2 \cdot 1) : 1 \cdot p y Q, 2, 1, - 1 \cdot p y Q, 1 - 3 p y Q, 2 \cdot 2, 1, 3, 2 \cdot 1

= 1 \cdot p y Q, 2, 1, - 1 \cdot p y Q, 1 - 3 p y Q, 2 \cdot 2, 1, 3, 2 \cdot 1

\frac{5 s + 13}{s ( s + 2 - 3 j )}

2 (9 n - 1) + 7 (n + 6 = - 60)

\frac{1}{( ( x + h ) - 3 ) ^{2}}

(x + x Δ)^{2}

\frac{1}{s ( s ^{2} + 7 )}

What is expand p(1,-3,2)yQ(2,1,-1) ?
The solution to expand p(1,-3,2)yQ(2,1,-1) is 1*pyQ,2,1,-1*pyQ,1-3pyQ,2*2,1,3,2*1