What is expand (x(x^2-3x-3))/(x+1) ?

The solution to expand (x(x^2-3x-3))/(x+1) is (x^3-3x^2-3x)/(x+1)

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expand (x(x^2-3x-3))/(x+1)

expand

\frac{x ( x ^{2} - 3 x - 3 )}{x + 1}

\frac{x ^{3} - 3 x ^{2} - 3 x}{x + 1}

Solution steps

\frac{x ( x ^{2} - 3 x - 3 )}{x + 1}

Expand

x (x^{2} - 3 x - 3) : x^{3} - 3 x^{2} - 3 x

= \frac{x ^{3} - 3 x ^{2} - 3 x}{x + 1}

\frac{s}{( s ^{2} + 1 ) ( s ^{2} - 1 )}

(\frac{- 40}{5} bi g)^{2} (5 - 40) 2

\frac{x + 5}{( x - 5 ) ^{2}}

4 x (2 x^{2} - 1 + c e^{- 2 x^{2}})

a (2, - 3) b (4, 2) c (4, - 3)

What is expand (x(x^2-3x-3))/(x+1) ?
The solution to expand (x(x^2-3x-3))/(x+1) is (x^3-3x^2-3x)/(x+1)