What is expand-sin(pit)(u(t-1)) ?

The solution to expand-sin(pit)(u(t-1)) is -tusin(pit)+usin(pit)

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expand-sin(pit)(u(t-1))

expand

- sin (π t) (u (t - 1))

- t u sin (π t) + u sin (π t)

Solution steps

- sin (π t) (u (t - 1))

Remove parentheses:

(a) = a

= - sin (π t) u (t - 1)

= - u sin (π t) (t - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = - sin (π t) u, b = t, c = 1

= - sin (π t) u t - (- sin (π t) u) \cdot 1

Apply minus-plus rules

- (- a) = a

= - t u sin (π t) + 1 \cdot u sin (π t)

Multiply:

1 \cdot u = u

= - t u sin (π t) + u sin (π t)

- 2^{2}

(1 + x^{4}) d y + x (1 + 4 y^{2}) d x

- 3 cos ((2 x^{3} + 2)^{3})

(sin (x))^{4}

x (- 2 + 3)

What is expand-sin(pit)(u(t-1)) ?
The solution to expand-sin(pit)(u(t-1)) is -tusin(pit)+usin(pit)